4/7x^2-4x

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Solution for 4/7x^2-4x equation: 


x in (-oo:+oo)

(4/7)*x^2-(4*x) = 0

(4/7)*x^2-4*x = 0

4/7*x^2-4*x = 0

DELTA = (-4)^2-(0*4/7*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)+4)/(4/7*2) or x = (4-16^(1/2))/(4/7*2)

x = 7 or x = 0

x in { 0, 7 }

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